A new proof of the generalized Craig-Sakamoto theorem
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摘要: 给出了推广的Craig-Sakamoto定理的一个新证明.设A,B是两个矩阵,对于任意的复数a,b满足det(I-aA-bB)=det(I-aA)det(I-bB)当且仅当AB=0.Abstract: We gave a new proof of the generalized Craig-Sakamoto theorem, which asserts that two normal matrices A and B satisfy det(I aA bB) = det(I aA)det(I bB) for all complex numbers a and b if and only if AB = O.
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Key words:
- eigenvalues /
- singular values /
- normal matrices /
- quadratic forms
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